p^2-p-342=0

Solution for p^2-p-342=0 equation:

p^2-p-342=0

We add all the numbers together, and all the variables

p^2-1p-342=0

a = 1; b = -1; c = -342;
Δ = b2-4ac
Δ = -12-4·1·(-342)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-37}{2*1}=\frac{-36}{2}
=-18
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+37}{2*1}=\frac{38}{2}
=19
$